Hi Year 2! This half term’s challenges are about multiplication and division. Write your answers on the blog. Good luck!
Bronze
Silver
Gold
GD
55 responses to “Year 2 Maths Challenge – Summer 1 2023”
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Bronze
2×4=8
8=4×2
2×8=16
Silver
They should buy bag 16 because it’s even -
Bronze
2×4=8
8=4×2
2×8=16
16=8×2
Silver
16 because it is even and you can split into 8 -
Silver
They should choose 16 because this number is equal
Gold
3 box’s with 10 in it because 10 times 3 =30 and its a even number -
4×5 is the odd one out because 40%2 is 20
20×0 is 20
2 x 10 is 20 -
Bronze:
2×4=8
8×4=32
8×2=16
2+4=6
8+4=12
2+8=10Silver:
They should buy the middle one because it has 16 and if u half it is 8 and I can’t half 15 and 11.
Gold:I would rather have 3 boxes with 10 in it because 3×10=30 and 5×5=25.They both have 20 in it so u can choose one.
GD:
The 3rd one is the odd one out because 20×0=20. -
2+4+8=14
2x4x8=64
8-4-2=2
Silver
They can choose the bag of 16 because it is an even number.
Gold
1) I would have a box of 3 with 10 biscuit
2) l will have one of them as their sum is equal.
GD
20×0 is the odd one out.
Because any number times with zero gives zero -
Silver challenge;
*16 will divide equally each friend will get 8 sweets. -
Bronze
2×4=8
2×8=16
4×2=8
8×4=32
8×2=16
4×8=32
Silver
They should buy 16 sweets in one bag because there is two friends share equally so 8×2=16 so you can give 8 to you friend and keep 8
Gold
I rather have 3 box with 10 biscuits because it has more biscuits.
I rather have both because 4×5= 20 also 2×10=20 -
Bronze
2×4=8
4×2=8
8×2=16
8×4=32Sliver
they buy 16 because they can divide it equally like 8.
Gold
I would rather have 3box with 10biscuits in 3×10=30
i would rather have 2box with 10 in 2×10=20GD
20×0=0 is the odd one. -
Bronze
2 × 4 = 8
8 × 2 = 16
8 × 4 = 32
Silver
16 ÷ 2 = 8 -
Bronze:
2×4=4
2×8=16
4×2=8
4×8=32
8×4=32 -
Bronze
2 x 4 = 8 4 x 2 = 8 8 / 2 = 4 8 / 4 = 2
8 x 4 = 32Silver
They should buy a bag of 16 sweets as they can eat 8 sweets each. 16 is an even number.
Gold
I’d rather have 3 boxes with 10 biscuits as you have more.
I don’t mind as they both have the same amount
GD.
20 x 0 = 0 is the odd amount as the rest equal 20.
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20×0 is the odd one out because it equals 0 and all the other sums equal 20
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Bronze
2×2=4
4×4=8
8×8=16
16×16=32
Silver
They should pick number 16 because 8×8=16
Gold
I would have 3 boxes with 10 biscuits because 3=30
I would have 2 trays because 10×10=20 easy to count them.
GD
20 is the odd one because 20×0 -
Gold
I would rather have 3 boxes of 10 because I will have 30 biscuits and that is more than 5 boxes of 5 biscuits which is 25I would have either of the trays because they both are equal with 20 apples.
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Gold- i would have 3 boxes of 10 biscuits as 10 times 3= 30
I would have any of them as they both have the same amount of apples7. The odd one is 20 times 0
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Bronze
2 x 4 = 8
4 x 2 = 8
8 / 2 = 4
8 / 4 = 2Silver
16 because 16 is an even number and they will get 8 sweets each
Gold
I would choose the 3 boxes that has 10 biscuits each because i will have 30 alltogether and the other boxes will only have 25 alltogether.
Both trays have the same amount of apples = 20 Apples
GD
40 / 2 = 20
4 x 5 = 20
20 x 0 = 0
2 x 10 = 2020 x 0 is odd one out
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Bronze
2×4=4
2×8=16
4×2=8
4×8=32
8×4=32Silver
16 because it can be split between 2 people .
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Bronze
8×2 = 16
4×2= 8
4÷2= 2
8÷2= 4
Silver
The bag with 16 sweets because 16÷2= 8
So each friend will have 8 sweets. -
200+48=248
200+40+8=248
15 is ood
16 is equal
11 is ood
They need to buy 16 bag of sweet -
2 4 8
4×2=8
2×4=8
8 / 4 = 2.
Silver
they should pick 16 as 16 can be split evenly between 2 with none left it will be 8 each -
Bronze
2*4=8
4/2=8
8/2=4
8*2=16Silver
They should buy bag 16 so they can share it equallyGold
I would have 3 boxes with 10 biscuits because its more
l would have because they the sameGD
20*0 =0 is the odd one out
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